Module 6 §3: Electromagnetism · Year 2
Force on a Current-Carrying Conductor
Revision notes on Force on a Current-Carrying Conductor for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
Module 6 §3: Electromagnetism · Year 2
Revision notes on Force on a Current-Carrying Conductor for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
The motor effect — a current-carrying conductor in a magnetic field experiences a force.
F = B I L sin θ
where θ is the angle between the current and the field.
The two extremes matter more than the formula
When the current is perpendicular to the field, sin θ = 1 and the force is maximum: F = BIL.
When the current is parallel to the field, sin θ = 0 and there is no force at all.
Fleming's left-hand rule gives the direction, for conventional current:
First finger — Field, from north to south.
seCond finger — Current, conventional, so positive to negative externally.
thuMb — Motion, the direction of the force.
Hold the three at right angles to each other. The left hand is for motors; the right hand is for generators, which is a distinction worth fixing early.
The force is perpendicular to both the current and the field — it is not along either of them. This is unlike every force met so far, and it is the source of most errors in this topic.
Defining the tesla — rearranging gives B = F/(IL), so one tesla is the flux density that produces a force of one newton on one metre of wire carrying one amp, placed at right angles to the field.
Example: this is the whole basis of the electric motor. A rectangular coil in a magnetic field has opposite currents in its two sides, so the forces on them act in opposite directions, producing a turning moment. A split-ring commutator reverses the current every half turn, so the torque always acts the same way round and the coil keeps rotating rather than settling.
Measuring B with a current balance — a stiff wire in a field is placed on a top-pan balance. Passing a current changes the reading by Δm, so the force is Δmg, and B = Δmg/(IL). Plotting the apparent change in mass against current gives a straight line whose gradient yields B, using all the readings rather than one.
Multiple choice and calculations for this topic are in the app, one question at a time. Written answers are marked against the specification and you get the mark scheme with the feedback.
Practise Force on a Current-Carrying Conductor