Module 6 §3: Electromagnetism · Year 2
Force on a Current-Carrying Conductor
Revision notes on Force on a Current-Carrying Conductor for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
Module 6 §3: Electromagnetism · Year 2
Revision notes on Force on a Current-Carrying Conductor for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
The motor effect — a current-carrying conductor in a magnetic field experiences a force.
F = B I L sin θ
where θ is the angle between the current and the field.
The two extremes matter more than the formula
When the current is perpendicular to the field, sin θ = 1 and the force is maximum: F = BIL.
When the current is parallel to the field, sin θ = 0 and there is no force at all.
Fleming's left-hand rule gives the direction, for conventional current:
First finger — Field, from north to south.
seCond finger — Current, conventional, so positive to negative externally.
thuMb — Motion, the direction of the force.
Hold the three at right angles to each other. The left hand is for motors; the right hand is for generators, which is a distinction worth fixing early.
The force is perpendicular to both the current and the field — it is not along either of them. This is unlike every force met so far, and it is the source of most errors in this topic.
Defining the tesla — rearranging gives B = F/(IL), so one tesla is the flux density that produces a force of one newton on one metre of wire carrying one amp, placed at right angles to the field.
Example: this is the whole basis of the electric motor. A rectangular coil in a magnetic field has opposite currents in its two sides, so the forces on them act in opposite directions, producing a turning moment. A split-ring commutator reverses the current every half turn, so the torque always acts the same way round and the coil keeps rotating rather than settling.
Measuring B with a current balance — a stiff wire in a field is placed on a top-pan balance. Passing a current changes the reading by Δm, so the force is Δmg, and B = Δmg/(IL). Plotting the apparent change in mass against current gives a straight line whose gradient yields B, using all the readings rather than one.
Reading is not revising. This topic has 4 questions in the app — multiple choice, calculations, and written answers marked against the mark scheme, point by point. Miss one and it comes back later with its options reshuffled, so you have to know it rather than remember where the answer sat.
20 minutes a day is free. No card, nothing to cancel — and the paid version never renews itself either.
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