Module 5 §2: Circular Motion · Year 2
Centripetal Acceleration
Revision notes on Centripetal Acceleration for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
Module 5 §2: Circular Motion · Year 2
Revision notes on Centripetal Acceleration for the OCR A-level Physics specification (H556). Free to read, with 4 practice questions in the app.
An object moving in a circle at constant speed is still accelerating, because velocity is a vector and its direction is changing continuously.
Centripetal acceleration — the acceleration of a body moving in a circular path, directed towards the centre of the circle.
a = v² / r
and using v = ωr,
a = ω² r
Why it points to the centre — over a short interval the change in velocity Δv points inwards, towards the centre. Since acceleration has the direction of Δv, the acceleration is centripetal: literally "centre-seeking".
The acceleration is perpendicular to the velocity — this is what allows the speed to stay constant while the direction changes. An acceleration component along the velocity would change the speed; one perpendicular to it only turns the object.
Example: the word "centrifugal" describes no force at all in this treatment. A passenger thrown against the side of a turning car feels pushed outwards, but what is actually happening is that the car is turning inwards beneath them while their body continues in a straight line, as Newton's first law requires. The inward force from the door is what makes them turn with the car.
Which form to use — a = v²/r when you know the linear speed, a = ω²r when you know the angular velocity. They are the same statement, related by v = ωr.
Example: a car of speed 12 m s⁻¹ on a bend of radius 30 m has a = 12² ÷ 30 = 4.8 m s⁻². For the same bend at twice the speed the acceleration would be four times as large, since a depends on v².
Increasing with speed, decreasing with radius — a tighter bend or a higher speed both demand a larger acceleration, and therefore a larger force. This is why speed limits fall on sharp bends: the required force rises with the square of the speed and the available friction does not.
Multiple choice and calculations for this topic are in the app, one question at a time. Written answers are marked against the specification and you get the mark scheme with the feedback.
Practise Centripetal Acceleration