Module 4 §3: Quantum Physics · Year 1
The Photon Model
Revision notes on The Photon Model for the OCR A-level Physics specification (H556). Free to read, with 5 practice questions in the app.
Module 4 §3: Quantum Physics · Year 1
Revision notes on The Photon Model for the OCR A-level Physics specification (H556). Free to read, with 5 practice questions in the app.
Photon — a quantum of electromagnetic radiation: a discrete packet of energy, not a continuous flow.
Photon energy —
E = hf
and since c = fλ,
E = hc / λ
where h is the Planck constant, 6.63 × 10⁻³⁴ J s.
What "quantised" means — energy arrives in whole packets or not at all. A source cannot emit half a photon, and an electron cannot absorb a fraction of one. This is the central break with classical physics, where energy could be transferred in any amount however small.
Example: a photon of frequency 5.0 × 10¹⁴ Hz carries E = (6.63 × 10⁻³⁴)(5.0 × 10¹⁴) = 3.3 × 10⁻¹⁹ J. That is a very small number in joules, which is why atomic physics usually uses electronvolts instead.
Energy and wavelength are inversely related — from E = hc/λ, a shorter wavelength means a more energetic photon. Gamma photons carry millions of times the energy of radio photons, which is why the hazard rises along the spectrum.
Intensity versus photon energy — this distinction does most of the work in this topic. The intensity of a beam depends on how many photons arrive per second. The energy of each photon depends only on the frequency. A very bright red lamp delivers enormous numbers of low-energy photons; a dim ultraviolet source delivers few high-energy ones.
The electronvolt — the energy transferred when an electron moves through a potential difference of one volt:
1 eV = 1.60 × 10⁻¹⁹ J
Convert to joules by multiplying by the electronic charge, and back by dividing.
Estimating h with LEDs — an LED emits photons of energy roughly equal to the work done moving one electron across it, so eV ≈ hc/λ at the threshold voltage where it just lights. Measuring V for LEDs of several known wavelengths and plotting V against 1/λ gives a straight line of gradient hc/e, from which h follows.
Reading is not revising. This topic has 5 questions in the app — multiple choice, calculations, and written answers marked against the mark scheme, point by point. Miss one and it comes back later with its options reshuffled, so you have to know it rather than remember where the answer sat.
20 minutes a day is free. No card, nothing to cancel — and the paid version never renews itself either.
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