Module 3 §4: Materials · Year 1
The Young Modulus
Revision notes on The Young Modulus for the OCR A-level Physics specification (H556). Free to read, with 6 practice questions in the app.
Module 3 §4: Materials · Year 1
Revision notes on The Young Modulus for the OCR A-level Physics specification (H556). Free to read, with 6 practice questions in the app.
The Young modulus — the ratio of tensile stress to tensile strain, for a material within its limit of proportionality:
E = stress ÷ strain = σ / ε
Since strain has no unit, the Young modulus has the same unit as stress: the pascal. Values for metals are large — steel is about 2.1 × 10¹¹ Pa — which is why they are usually quoted in GPa.
What it means — the Young modulus measures stiffness: how much stress is needed to produce a given strain. A large Young modulus means a material that resists being stretched. It is a property of the material, so every steel sample has the same Young modulus regardless of its dimensions.
Stiffness is not strength — a stiff material resists deformation; a strong material resists breaking. Glass has a high Young modulus and is stiff, yet it is brittle and breaks easily. The two properties are independent and describe different things.
In terms of measurable quantities —
E = FL / (Ax)
which is what you actually calculate from an experiment: force, original length, cross-sectional area and extension.
Measuring E for a wire — a long, thin wire is clamped at one end and loaded at the other, with a marker on the wire read against a fixed rule. The diameter is measured with a micrometer at several points along the wire and averaged, since wires are rarely perfectly uniform.
Why the wire is long and thin — a long wire gives a larger extension for the same strain, making the extension easier to measure accurately. A thin wire gives a larger stress for the same load, so smaller masses produce measurable strains. Both choices reduce the percentage uncertainty in the final answer.
Getting E from a graph — plot stress against strain and take the gradient of the straight section. Using a gradient rather than a single pair of readings averages out random error and shows immediately where the straight-line region ends.
Example: a stress of 4.0 × 10⁷ Pa producing a strain of 2.0 × 10⁻⁴ gives E = (4.0 × 10⁷) ÷ (2.0 × 10⁻⁴) = 2.0 × 10¹¹ Pa.
Reading is not revising. This topic has 6 questions in the app — multiple choice, calculations, and written answers marked against the mark scheme, point by point. Miss one and it comes back later with its options reshuffled, so you have to know it rather than remember where the answer sat.
20 minutes a day is free. No card, nothing to cancel — and the paid version never renews itself either.
Start The Young Modulus