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IGCSE §3: Waves · IGCSE

Total Internal Reflection

Revision notes on Total Internal Reflection for the OCR A-level Physics specification (H556). Free to read, with 5 practice questions in the app.

Total internal reflection (TIR) — all of the light is reflected back into the denser medium at a boundary, with none refracting out.

Two conditions must both hold:

  1. The light is travelling from a denser medium into a less dense one — glass to air, water to air, never the other way.
  2. The angle of incidence is greater than the critical angle.

Critical angle (c) — the angle of incidence in the denser medium at which the refracted ray emerges along the boundary, at 90° to the normal. Below it, light refracts out (with some weak reflection); above it, all the light reflects.

The critical angle is related to the refractive index by:

sin c = 1 / n

A larger refractive index gives a smaller critical angle, so light is trapped more easily. Glass with n = 1.5 has a critical angle of about 42°, and water with n = 1.33 about 49°.

Optical fibres — a thin core of glass surrounded by cladding of lower refractive index. Light entering at a shallow angle strikes the core–cladding boundary above the critical angle every time, so it is totally internally reflected along the fibre, following it round bends with almost no loss.

Uses: communications, carrying telephone and internet data as pulses of infrared, with far greater capacity and much less signal loss than copper cable; and endoscopes, where one bundle of fibres carries light in to illuminate the inside of the body and another carries the image back out, allowing a surgeon to see inside without major surgery.

Prisms — a right-angled glass prism turns light through 90° or 180° by total internal reflection, because 45° exceeds the critical angle of glass. Used in periscopes and in binoculars, where prisms fold a long light path into a short body. A prism gives a brighter, sharper image than a mirror, because a mirror loses some light at its silvered backing and can produce faint double images.

Example: light inside a fibre with n = 1.5 meets the wall at 80° to the normal. Since 80° is well above the 42° critical angle, none escapes. Bend the fibre too sharply and the angle can fall below 42°, at which point light leaks out and the signal is lost — which is why fibre runs have a minimum bend radius.

5 questions on Total Internal Reflection

Reading is not revising. This topic has 5 questions in the app — multiple choice, calculations, and written answers marked against the mark scheme, point by point. Miss one and it comes back later with its options reshuffled, so you have to know it rather than remember where the answer sat.

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